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Hola User_________________
Here is Your Answer...!!!!
__________________________
↪Actually welcome to the Concept of the SHM ....
↪Basically the KINETIC ENERGY in SHM IS GIVEN BY
⭐↪K.E. = 1/2 K ( A^2 - X^2 )
↪since we know that. ..
↪K = M w^2
↪substituting we get as ...
↪K.E = 1/2 M w^2 ( A^2 - X^2 )
↪since here , M= 10 kg , A = 10 m , X = 5 m and w = pi
_________________________
#MAD FOR MAX
Here is Your Answer...!!!!
__________________________
↪Actually welcome to the Concept of the SHM ....
↪Basically the KINETIC ENERGY in SHM IS GIVEN BY
⭐↪K.E. = 1/2 K ( A^2 - X^2 )
↪since we know that. ..
↪K = M w^2
↪substituting we get as ...
↪K.E = 1/2 M w^2 ( A^2 - X^2 )
↪since here , M= 10 kg , A = 10 m , X = 5 m and w = pi
_________________________
#MAD FOR MAX
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[0010001111]... Hello User... [1001010101]
Here's your answer...
m = 10 kg
A = 10 m
T = 2 s
Equation of SHM is x = A sin(wt+§)
where x is the displacement from the mean position and § is the initial phase.
Since the particle starts from the mean position, its §=0
T = 2 pi/w
w = pi
5 = 10 sin (pi×t)
pi×t = pi/6
t = 1/6 second
v = Aw cos wt
= 10×pi×3^½/2
= 5 pi root 3
KE = ½mv² = ½×10×25×pi²×3
≈ 3701.1 J
[0110100101]... More questions detected... [010110011110]
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Here's your answer...
m = 10 kg
A = 10 m
T = 2 s
Equation of SHM is x = A sin(wt+§)
where x is the displacement from the mean position and § is the initial phase.
Since the particle starts from the mean position, its §=0
T = 2 pi/w
w = pi
5 = 10 sin (pi×t)
pi×t = pi/6
t = 1/6 second
v = Aw cos wt
= 10×pi×3^½/2
= 5 pi root 3
KE = ½mv² = ½×10×25×pi²×3
≈ 3701.1 J
[0110100101]... More questions detected... [010110011110]
//Bot UnknownDude is moving on to more queries
//This is your friendly neighbourhood UnknownDude
//Lemme know if I'm right
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