Question

I just need the process

Answer 1

Step-by-step explanation:

2 is the write answer for this

Answer 2

Step-by-step explanation:

We have,

$f(x) = [x] \sin \bigg( \frac{\pi}{ [x + 1]} \bigg)$

Clearly, $\frac{\pi}{[x+1]}$ is not defined when [x+1] = 0

Now,

$[x + 1] = 0 \implies [x] + 1 = 0$

$\implies [x] = - 1$

$\implies\:\:x \in [-1,0)$

So,

$dom \{f \} \in \: R - [ - 1,0)$

$\implies dom \{f \}\: \in \: ( - \infty , - 1) \: \cup \: [ 0 , \infty )$