Question

I know a family in which there are many children. Each boy in this family has as many sisters as brothers but each girl has twice as many brothers as sisters. How many girls and boys are there?

Answer 1

Answer:

Step-by-step explanation:

Explanation :

Lets assume no. of girls = x and boys = y

y = (x+1) ----------- (i)

As each boy have equal no. of sisters and brothers and he is not included in brothers.

so, 1 is for him in (x+1).

y = 2(x-1) ------ (ii)

as each girl have (x-1) sisters.

By solving eq. (i) and(ii)

girls = 3 and boys = 4

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Answer 2

3 sisters, 4 brothers

(x+1)=2(x-1)

Sorry if short. I like answering questions that can be solved mentally.

Edit:

After much prodding, had to include this,

x = number of girls = number of brothers any guy in that family will have

hence, x+1 = number of total guys,

hence, x-1 = number of sisters any girl in the family will have

For any girl in that family,

number of brothers = 2 x number of sisters

Hence, (x+1)=2(x-1)

solving for x, number of girls = 3, number of boys = 4
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