I know I ask too many questions but I need help. The first pic all and the second one the seventh.
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First paper answer
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Heya!!!
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a. (d) 24
b. (c) W
c. (a) 2bc
d. (d) 0.05
e. (b)x–2
f. (d) 26.352
7. L.C.M.(48, 72, 108):
48=2×2×2×2×3
72=2×2×2×3×3
108=2×2×3×3×3
Thus, L.C.M.(48, 72, 108)=(2×2×3)×2×2×2×3×3×3=2592sec.
2592sec=(2592/60)min.=43.2min
OR 00:43:12
Thus, all the three lights will again change simultaneously at:
=>8:20:00+00:43:12
=>8:63:12
OR
=> At, ...09:03:12
I hope it helps you ^_^
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