Science, asked by iraagrawal3, 1 month ago

i know that we use v²-u²/2a to derive formula...but what is wrong here? I should be getting mv²/2.
(u=0)​

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Answered by Anonymous
3

Hey mate,

here's the correct formula:

Expression for Kinetic energy(Ek)-

Consider an object with mass m, moving with initial velocity u. Let a force F, act on it causing a displacement s, along the direction of force and accelaration. Let the object attain final velocity v.

We know

F = m a --- 1  \\ By \:  position \:  velocity \:  relation  \\we  \: have,  \: V2 = u2 + 2as  \\ </p><p>or\: s = v2 -u2 / 2a ------ 2  \\ The \:  work  \: done \:  by \:  the  \: force  \\ W = F x s ------ 3  \\ Substituting \:  1 \:  and  \: 2 \:  in  \: 3  \\ W = (ma) × (v2 - u2/2a)  \\ W = m/2 (v2 - u2)  \\ W = 1/2 mv2 - 1/2 mu2 ----- 4  \\ For \:  an  \: object  \: to \:  be \:  at \:rest \:  in  \: the \:  beggining, \\  u = 0 \\Therefore,  \\ W = 1/2 m {v}^{2}   \\ W = Ek ( Ek = kinetic\: energy)  \\ Therefore, \: Ek = 1/2 m {v}^{2}

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