I know the answer but please solve step by step and the isAnswer is D=2, s13=1155
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a=3
The formula for finding nth term in an AP: Tn = a + (n - 1) d
Given: a₁₆=33
∴3+ (16-1)d=33
15d=30
d=2
Sum of first n terms of an AP: S =(n/2)[2a + (n- 1)d]
S₁₃=(13/2)(2*3+12*2)
=13/2(30)
=195
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