(i) kx² + 2x + 1 = 0
Answers
Answered by
3
Answer:
For real and distinct roots
b {}^{2} - 4ac \: = 0b
2
−4ac=0
(2) {}^{2} - 4(k)(1) = 0(2)
2
−4(k)(1)=0
4 = 4k4=4k
k \: = 1k=1
Step-by-step explanation:
plzz massage me
Similar questions