Question

i. kx2 – 4x – 5 = 0
ii. (k – 4)x2 + 2(k – 4)x + 4 = 0
Value of k for which the equations have equal roots

Answer 1

Answer:

$16 + 20k = 0$

$k = \frac{2}{5}$

Step-by-step explanation:

for equal roots;

${b}^{2} - 4ac = 0$

then;

I)

${4}^{2} - 4 \times k \times - 5 = 0$