Math, asked by i746767, 1 year ago

I ll give all my point if someone answers me well i promise!! (105)!
pllzzzz good answers pllzzzzzzz i have a project to finish for tomorrow

I have to make a demonstration I need help pls


There are several cases where the incident ray has as its point of departure a focus of hyperbole

angle of incidence = angle of reflection
the incidence point(A)=(m,n)

The normal vector (v2) has (b(square)m;-a(square)n)


The question: make a demonstration on the trajectory of the ray reflected by a hyperbolic mirror when the incident ray starts from a focus

PS: sorry if their is mistakes i had the broblem in frensh and i don't lean maths in english


it's urgent I need an answer as soon as possible
thank you!

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i746767: GOOODDD answer plzzzzzzz
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i746767: more than 105 points I despair :'(

Answers

Answered by AryanTennyson
0
the angles α  and β  between the tangent line and the straight lines drawn from the hyperbola foci to the given point are congruent:  
Recall the physical  law of reflection:  the angle of incidence is equal to the angle of reflection measured from the normal.  It is consistent with the geometric optical 
properties above.

The reflected ray R u can be written in parametric form as shown in Equation 1 above, where v = v ( u ) is its direction. We can write q = ξu , for some positive number ξ . Since q − c 2 = r 2 , and c − o = dw , ξ must be the smallest positive real root of the quadratic equation Note that, if α is the angle formed by the vectors u and w , the maximum angle α MAX is achieved when the incident and reflected rays are tangent to the sphere, in which case.

i746767: i gave you an exelent even if i didn't undestand can you summurize plz more simple pls :) :)
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