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If a^2+1/a^2=18 and his not equal to 0 find a³-1/a³
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First of all the question is unclear, you brackets are missing, I have no clue if you meant (a² + 1) / a² = 18 or a² + (1/a²) = 18 ,
17 a² = 1
a² = 1/17
a = 1/√17
So, a³ = 1/√17³
(a³-1)/a³ = 1 - 1/a³ = 1 - √17³
Or if you mean the other way,
a² = [18 ± √(324 - 4)] / 2
a = √(9 ± 4√5)
Since this gives logrithmninc answer I suppose your answer is 1 - √17³.
NEXT TIME PLEASE GIVE CLEAR QUESTION WITH BRACKETS, maths is magical and can have various meanings.
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