I'll mark u as brenliest
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Hi there,
Here is your answer
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let x =√6+√6+√6.......... squaring both sides you’ll get
x²= 6+x {√6+√6.......... =x }
x² -x -6=0
x² +2x-3x=0
taking common
x(x+2)-3(x+2)=0
(x+2)(x-3)=0
x=-2,3
-2 is not the answer as x is a square root and real number it must be positive, it also has the value of 3
Ans=3
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Hope It helps
Best of Luck
Please Mark As Brainleast
Answered by
0
Answer:
- pls mark as brainliest
Step-by-step explanation:
let x=root6+root6........infinitt
by squaring
x2=6+root6+root6.....
x2=6+x
x2-x-6=0
x2-3x+2x-6=0
x(x-3)+2(x-3)=0
(x-3)(x+2)=0
x=3,x=-2
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