Math, asked by PalakRathi1306, 1 year ago

I'll mark u as brenliest​

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Answered by Anonymous
0

Hi there,

Here is your answer

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let x =√6+√6+√6..........  squaring both sides you’ll get

x²= 6+x     {√6+√6.......... =x }

x² -x -6=0

x² +2x-3x=0

taking common

x(x+2)-3(x+2)=0

(x+2)(x-3)=0

x=-2,3

-2 is not the answer as x is a square root and real number it must be positive, it also has the value of 3

Ans=3

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Hope It helps

Best of Luck

Please Mark As Brainleast

Answered by bhanuprakashreddy23
0

Answer:

  • pls mark as brainliest

Step-by-step explanation:

let x=root6+root6........infinitt

by squaring

x2=6+root6+root6.....

x2=6+x

x2-x-6=0

x2-3x+2x-6=0

x(x-3)+2(x-3)=0

(x-3)(x+2)=0

x=3,x=-2

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