Math, asked by PalakRathi1306, 1 year ago

I'll mark u as Brenliest​

Attachments:

Answers

Answered by apurvaa200297
3

Answer:

15m

Step-by-step explanation:

The longest pole can be kept at the diagonal

For the diagonal to be longest the two other sides should also be long

12m,9m, and required diagonal form a right angled triangle with hypotenuse 15.

Answered by Anonymous
25

\huge{\mathfrak{\red{\underline{\underline{Answer :-}}}}}

(B) 17m

\large{\mathrm{\gray{Given :-}}}

Length = 12m

Breadth = 9m

Height = 8m

\large{\mathrm{\gray{To \: Find:-}}}

Length of longest pole that can be placed in the room. (Diagonal)

\large{\mathrm{\gray{Solution :-}}}

Using Formula

\huge{\boxed{\boxed{\bf{\red{Diagonal = l^{2} + b^{2} + h^{2}}}}}}

______________[Put Values]

\bf{Diagonal ={\sqrt (12)^{2}+ (9)^{2} + (8)^{2}}}

\bf{Diagonal = {\sqrt144 + 81 + 64}}

\bf{Diagonal = {\sqrt289}}

\bf{Diagonal = 17}

\huge{\boxed{\boxed{\bf{\red{Diagonal = 17 m}}}}}

Member of "The sheild"

Leader of "The sheild"

Attachments:
Similar questions