Math, asked by lourdvimala1970, 11 months ago

I'll mark you as brainlist if u ans both​

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Answered by crdsa7001
1
  1. Answer:

HCF

= 11

THANKS MARK IT AS BRAINLIEST ANSWER

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Answered by Anonymous
1

27. We have to find the LCM of 40 cm, 42 cm and 45 cm to get the required minimum distance. Because we are asked the minimum distance

Now,

40 = 2 × 2 × 2 × 5,

42 = 2 × 3 × 7

45 = 3 × 3 × 5

∴ LCM (40, 42, 45) = 2 × 3 × 5 × 2 × 2 × 3 × 7 = 30 × 12 × 7 = 210 × 12 = 2520

Minimum distance each should walk 2520 cm. so that, each can cover the same distance in complete steps.

OR

By Euclid’s Division lemma

726 = 275 ×2+176

275 = 176 ×1 + 99

176 = 99 ×1+77

99 = 77 × 1+22

77= 22 ×3 + 11

22 = 11 × 2 + 0

HCF = 11

Hope it helps you mark as brainliest please

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