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HCF
= 11
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27. We have to find the LCM of 40 cm, 42 cm and 45 cm to get the required minimum distance. Because we are asked the minimum distance
Now,
40 = 2 × 2 × 2 × 5,
42 = 2 × 3 × 7
45 = 3 × 3 × 5
∴ LCM (40, 42, 45) = 2 × 3 × 5 × 2 × 2 × 3 × 7 = 30 × 12 × 7 = 210 × 12 = 2520
Minimum distance each should walk 2520 cm. so that, each can cover the same distance in complete steps.
OR
By Euclid’s Division lemma
726 = 275 ×2+176
275 = 176 ×1 + 99
176 = 99 ×1+77
99 = 77 × 1+22
77= 22 ×3 + 11
22 = 11 × 2 + 0
HCF = 11
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