Question

I'll mark you brainlist plz answer this question fast and don't spam 2x²-8√2x+16=0​

Answer 1

we can write above equation

as 2x^2 -4√2x-4√2x+16=0

2x(x-2√2)-4√2(x-2√2)=0

(x-2√2)(2x-4√2)=0

so, x=2√2,2√2

please mark as brainliest❤

Answer 2

==> 2x² - 8√2x + 16 = 0

==> 2x² - 4√2x - 4√2x + 16 = 0

==> √2x(√2x - 4) - 4(√2x - 4) = 0

==> (√2x - 4)(√2x - 4) = 0

Here,

☛ √2x - 4 = 0

☛ √2x = 4

☛ x = 4/√2

☛ x = 2√2

Zeroes are : 2√2 , 2√2