Question

I'LL MARK YOUR ANSWER AS THE BRAINIEST A person of mass m kg is standing on a lift . If the lift moves vertically upwards according to given v-t graph then find out the weight of a man at the following instants(g=10 m/s^2) t=1s t=8s t=12 s

Answer 1

Answer:

Here is your answer !

Explanation:

Since, at time 1sec the acceleration will be 10m/s

2

.

The weight is given as,

W=m(g+a)

=M(10+10)

=20M

Since, at time 8sec the acceleration will be 0m/s

2

.

The weight is given as,

W=m(g+a)

=M(10+0)

=10M

Since, at time 12sec the acceleration will be −10m/s

2

.

The weight is given as,

W=m(g+a)

=M(10−10)

=0

Thus, the weight of man at 1sec, 8sec and 12sec is 20M, 10M and 0 respectively.