Question

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If the distance between sun and earth is 1.5x 108Km and time period of revolution of earth around the sun is 1 year, then find the tangential speed of earth around the sun.​

Answer 1

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Answer 2

Explanation:

The average distance of the Earth from the Sun is spproximately 150 million km or 1.5×1011m

The orbit of the Earth around the sun is roughly circular (more eliptical really, but let's keep it simple), with a period of roughly 365 days.

So the path that the Earth traverses in 365 days is approximately the circumference of a circle of radius 1.5×1011m.

Use the formula C=2πr to find that this is about 9.4×1011m.

The number of seconds in 365 days is:

365⋅24⋅60⋅60=31536000

So the tangential velocity of the Earth is approximately:

9.4×10113.1536×107≈3×104ms−1

That is 30 km per second.

If you want more accuracy, get more accurate figures for the distance of the Earth from the sun at perihelion/aphelion and use a more accurate figure for the orbital period.

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