Question

I m^2+n^2=121 and mn=20, the positive value of (m-n) will be?

Answer 1

Answer:

Step-by-step explanation:

m^2+n^2=121

mn=20

Therefore m^2+n^2-2mn=121-2mn

m^2+n^2-2(20)=121-2(20)

(a-b)^2=a^2+b^2-2ab

So,

(m-n)^2=121-40

(m-n)^2=81

(m-n)=√81

(m-n)=9