I’m a 2-digit number. The digit in the units place is four times the digit in the tens place and sum of the digits is equal to 10. Who am I?
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Answer:
10x+y=10×2+8=28
Step-by-step explanation:
Let's take number as 10x+y
As per question,
y=4x, and
x+y=10
So, x+4x=10
5x=10
x=2
y=2×4=8
So, number is 10x+y=10×2+8=28
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