Question

I'm a sample bag of m&m's there are 5 brown, 6 yellow, 4 blue, 3 green, and 2 orange. What is the probability of getting 3 yellow m&m's if 3 are taken at a time?

Answer 1

There are a total of 5+6+4+3+2=20 M&Ms in the bag.  Since there are 6 yellow M&Ms in the bag, there's a 6/20 probability that the first M&M will be yellow.  Then, there are 5 more yellow M&Ms and 19 more total M&Ms in the bag, so there is a 5/19 chance the next M&M will be yellow.  Finally, there are 4 more yellow M&Ms in the bag and 18 total M&Ms, so there is a 4/18 chance the last M&M will be yellow.

Multiplying these together, we have:

(6*5*4)/(20*19*18)

This simplifies to:

1/57

Therefore, there is a 1/57 probability that all M&Ms will be yellow.