I'm a two digit number the digit in the tens place is 2 more than the digit in the ones place the sum of the digits is 8 so what is the answer
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Answer:
That number is 53
Step-by-step explanation:
let the tenth place digit be X+2
And unit place digit be X
The sum of that two digits is 8 (GIVEN)
Therefore (X+2)+(X)=8
2X+2 =8
2X =8-2
2X =6
X =6/2
X =3
Tenth place digit=X+2
=3+2
=5
AND unit place digit=X
X=3
Therefore that two digit number is 53.
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