I'm asking a difficult question and whosoever will answer this correct and accurate , I'll Mark it as brainliest and will also thank the answer Q- how we can make the electronic configuration of elements having atomic no 100 or more
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Explanation:
For elements of atomic number more than 20
Take an example of Iron which has atomic number 26
First calculate the electronic configuration of its sub- shells.
Fe(26): 1s2 2s2 2p6 3s2 3p6 4s2 3d6.
Then, calculate the electronic configuration of its shells.
Fe(26): 2 8 14 2.
EXCEPTION: Chromium (Atomic No.-24) and Copper (Atomic No.-29)
Cr(24): 1s2 2s2 2p6 3s2 3p6 4s1 3d5. Cr(24): 2 8 13 1
Cu(29): 1s2 2s2 2p6 3s2 3p6 4s1 3d10. Cu(29): 2 8 18 1.
For the elements whose atomic number is greater than 21, it will be easy if you calculate the electronic configuration of the sub-shells of that element and then calculate the electronic configuration of the shells.
By this way we can find it easily
Hope it helps
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