I'm desperate PLS HELP! Math Class 9 ICSE. I Will forever be grateful <3 I promise up to 100 points if you can actually help. (I'm assigning with only 10 points bc some write nonsense for points) Please help!
Answers
Step-by-step explanation:
But some women worked in professions and jobs available mostly to men. There were women doctors, lawyers, preachers, teachers, writers, and singers. By the early 19th century, however, acceptable occupations for working women were limited to factory labor or domestic work
Step-by-step solutions:
Q1) LHS
(2+√3)(2+√3)/(2-√3)(2+√3)
=> (2+√3)²/2²-(√3)²
=> 4+4√3+3
=> 7+4√3
RHS
a+b√3
hence, a=7 & b=4
Q2) Given: a+(1/a) = 6
=> (a²+1)/a = 6
=> a²+1 = 6a
=> a²-6a = -1
=> a²-6a+9 = 8 (adding 9 on both sides)
=> (a-3)² = 8 (after factorizing)
=> a-3 = ±2√2
=> a = 3+2√2 or 3-2√2
(i) a-(1/a)
=> (3±2√2)-{1/(3±2√2)}
=> ±4√2 [after simplifying]
(ii) a²-(1/a²)
=> {a+(1/a)}{a-(1/a)}
=> 6 * ±4√2
=> ±24√2
Q3)Given: 4x-y=6, 5y-4x=7
using cross multiplication method:
x/(b1c2-b2c1) = y/(c1a2-c2a1) = 1/(b2a1-b1a2) To be honest I didn't knew this method till now
=>x/32 = y/48 = 1/16
=> x/2 = y/3 = 1
hence, x=2 & y=3
Q4) (2a+b)²-6a-3b-4
=> (2a+b)²-3(2a+b)-4
Let 2a+b = x
then, x²-3x-4
=> (x+4)(x-1)
=> (2a+b+4)(2a+b-1)
Q5) ATQ
(x+x+2+x+4+x+6+x+8)/5= 11
=> (5x+20)/5=11
=> x+4=11
=> x = 7
mean of first 3 observations:
(x+x+2+x+4)/3 = m
(7+7+2+7+4)/3=m
27/3=m
m = 9
Q6)Let the req distance be 'd'
after putting P(2,2) and Q(5,4) on graph we get:
|x1-x2| (r)= 3 & |y1-y2| (s)= 2
Using Pythagoras theorem:
d = √(r²+s²)
= √(3²+2²)
=√13
~3.6 units
Hope u get it
I am also in class 9 CBSE
Happy to help