English, asked by mayuri14121988, 1 month ago

I'm from Army Public School Ranchi grade 6th ,

Please , can anyone tell me the answer of the book Honeysuckle chapter - 1 who did Patrick's homework ? of grid puzzle 6th number in Down.
Can anyone help me ??​

Answers

Answered by Anonymous
0

Answer:

Step-by-step explanation:

Given that:

In triangle PQR, PS is perpendicular to QR. find the sides marked a and b. if PR=41, QS=12 and SR=40

To find: a and b

Solution:

In ∆PQR,

As PS is perpendicular.

∆PSR is right angle triangle,right angle at S

here Base(SR)=40 cm

Hypotenuse(PR)=41 cm

Perpendicular(PS)=a=?

To find PS,apply Pythagoras theorem in ∆PSR

\begin{gathered}( {PR)}^{2} = ( {SR)}^{2} + ( {PS)}^{2} \\ \\ ( {41)}^{2} = ( {40)}^{2} + {a}^{2} \\ \\ {a}^{2} = 1681 - 1600 \\ \\ {a}^{2} = 81 \\ \\ \bold{\red{a = 9} }\\ \\ \end{gathered}

(PR)

2

=(SR)

2

+(PS)

2

(41)

2

=(40)

2

+a

2

a

2

=1681−1600

a

2

=81

a=9

Thus,

PS= a= 9cm

Now,

∆PSQ is right angle triangle,right angle at S

here Base(SQ)=12 cm

Hypotenuse(QP)=b=?

Perpendicular(PS)=9 cm

Apply Pythagoras theorem in ∆PSQ

\begin{gathered}( {QP)}^{2} = ( {SQ)}^{2} + ( {PS)}^{2} \\ \\ ( {QP)}^{2} = {b}^{2} = ( {12)}^{2} + ( {9)}^{2} \\ \\ {b}^{2} = 144 + 81 \\ \\ {b}^{2} = 225 \\ \\ b = \sqrt{225} \\ \\ \bold{\green{b = 15}} \\ \\ \end{gathered}

(QP)

2

=(SQ)

2

+(PS)

2

(QP)

2

=b

2

=(12)

2

+(9)

2

b

2

=144+81

b

2

=225

b=

225

b=15

Thus,

b= 15 cm.

Final Answer: a= 9 cm,b= 15 cm

Hope it helps you.

Explanation:

  • please make it a brainliest answer.
Answered by LaRouge
0

Answer:

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