Question

I'm giving all my points. Please answer these seriously.

1. In a ΔABC, if AB = AC and BC is produced to D such that ∠ACD = 10° then ∠ACD = ?
2. In a ΔABC if ∠A = 45°, determine the shortest and largest sides of the triangle.
3. AD is an altitude of an isoceles triangle ABC in which AB = AC. Prove that ΔBAD=ΔDAC.
4. In the given figure if AD is the bisector of ∠A, show that AC>CD. [FIGURE below].
5. In the given figure ΔCPD=ΔBPD and AD is the bisector of ΔBAC. Prove that ∠BAP=∠CAP and hence BP=CP. [FIGURE below]

Answer 1

Answer:

1. if angle ACD is 10° the Angle ACD is also 10

2.The Shortest side is BC and AC and AB both are Largest sides because it is an Isosceles Triangle