I'm having problem in this question...Can anyone give me the solution of that?
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Answered by
1
Answer:
uniform velocity for 15 s = 30m/s
Distance for 15 s = 30*15= 450m
we know
initial velocity of the body = 30m/s
acceleration = 8m/s²
time = 10s
distance covered = 30*10+1/2*8*10²
= 300+400
= 700m
final velocity = 30 + 8*10
= 30+80
= 110m/s
distance covered for next 15s at a retardation of 6m/S²
= 110*15+ 1/2*-6*15²
= 1650+ -3*225
= 1650-675
= 975m
therefore, total distance travelled = 450+700+975
= 2075m
total time talken = 15+10+15 = 40s
therefore , average velocity = 2075/40= 51.875 m/s
Ans = 2075m, 51.875m/s.
Answered by
1
Answer:
(i) the total distance covered by the object is 1530m
(ii) no idea
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