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Which grade question is it?
moosee:
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Roots are same, so Discriminant (D) will be zero
Therefore, b² - 4ac = 0 ..... since, D = b² - 4ac
So, [-2(ac + bd)]² - 4 × (a² + b)² × (c² + d²) = 0
Now you can solve....
Therefore, b² - 4ac = 0 ..... since, D = b² - 4ac
So, [-2(ac + bd)]² - 4 × (a² + b)² × (c² + d²) = 0
Now you can solve....
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