Question

I'm the lab a beaker is at a temperature of 64 degree Celsius . it is put in a freezer and it's temperature is reduced at the rate of 2 degree Celsius per min
(ii) what will be the temperature 36 min after it is put in the freezer​

Answer 1

Answer:

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Step-by-step explanation:

temperature = 64°C

time =2°C per minute

temperature in 36min= 36×2

=72°C

Now,

64°C-72°C

= -8°C

hope it helps you

Answer 2

In 1 min. Temperature reduced by 2°C

So, in 36 min. Temperature reduced by

36 x 2 = 72°C

Hence, the temperature after 36 min. is

(64 - 72)°C = -8°C ___________(Ans.)

Hope it helps...

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