i m unable to identify my mistake
tell me. where i m doing wrong
^_^
give me a brief explanation
^_^irrelevant ans will be reported
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JinKazama1:
your way of asking questions is really nice.
Answers
Answered by
1
see here x=root 2 a andy=root 3 b..
you have written correct answer till the 2nd stage but at the final step you have done mistake in taking the value of x and y.
hope my answer helped you.
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Answered by
5
Hello Madam☺️
Here Is Your Answer☺️
As We Know,,,
(A+B)^2=(A)^2+2.A.B+B^2
So, Think Clearly,
(√2a)^2=(A)^2
And,
(√3b)^2=(B)^2
If You Compare ,,
(A)^2+2.A.B+B^2 & (√2a)^2+2×√2a×√3b×(3b)^2
You Will Get, (√2a+√3b)^2
There Are No Calculation Like,
(√2a)^2=2a^2
Because Comparing Them,
(√2a)^2=(A)^2
Hope Your Doubt Cleared☺️✌️
Have a Great Day Ahead
Here Is Your Answer☺️
As We Know,,,
(A+B)^2=(A)^2+2.A.B+B^2
So, Think Clearly,
(√2a)^2=(A)^2
And,
(√3b)^2=(B)^2
If You Compare ,,
(A)^2+2.A.B+B^2 & (√2a)^2+2×√2a×√3b×(3b)^2
You Will Get, (√2a+√3b)^2
There Are No Calculation Like,
(√2a)^2=2a^2
Because Comparing Them,
(√2a)^2=(A)^2
Hope Your Doubt Cleared☺️✌️
Have a Great Day Ahead
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