Math, asked by trisha10433, 1 year ago

i m unable to identify my mistake
tell me. where i m doing wrong
^_^
give me a brief explanation
^_^irrelevant ans will be reported

Attachments:

JinKazama1: your way of asking questions is really nice.
as1965286p7d7zu: you solved this question correctly
as1965286p7d7zu: remember the identity (a+b) ^2
as1965286p7d7zu: put (root 2a+root 3b)^2
as1965286p7d7zu: and check that ans is comes out to be as similar to that question or not
JinKazama1: @Trisha, I am appreciating

Answers

Answered by Anupamasrimaa
1

(x \times y) ^{2}  = x {}^{2}  + 2xy + y {}^{2}
see here x=root 2 a andy=root 3 b..
you have written correct answer till the 2nd stage but at the final step you have done mistake in taking the value of x and y.
hope my answer helped you.
Attachments:

as1965286p7d7zu: mention not
Anupamasrimaa: are you able to understand what i am trying to say?
Anupamasrimaa: nice
Answered by InvincibleBoy
5
Hello Madam☺️

Here Is Your Answer☺️

As We Know,,,

(A+B)^2=(A)^2+2.A.B+B^2

So, Think Clearly,

(√2a)^2=(A)^2

And,

(√3b)^2=(B)^2

If You Compare ,,

(A)^2+2.A.B+B^2 & (√2a)^2+2×√2a×√3b×(3b)^2

You Will Get, (√2a+√3b)^2

There Are No Calculation Like,

(√2a)^2=2a^2

Because Comparing Them,

(√2a)^2=(A)^2

Hope Your Doubt Cleared☺️✌️

Have a Great Day Ahead
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