Math, asked by priyanshukumar2177, 1 month ago

I make you a Brainlist plz give answer my question.
simplify=—3 upon root3 +root2 — 3 root2 upon root6 +root 3 + 4 root3 upon root6 +root2 ​

Answers

Answered by mh5767187
1

Answer:

Simplifying 1st part

 \frac{3 \sqrt{2} }{ \sqrt{3}  +  \sqrt{6} }  \times  \frac{ \sqrt{3}  -  \sqrt{6} }{ \sqrt{3}  -  \sqrt{6} }

 \frac{3 \sqrt{2 }  \times ( \sqrt{3} -  \sqrt{6}  }{ {( \sqrt{3)} }^{2}  -  {( \sqrt{6)} }^{2} }  =  \frac{3 \sqrt{2}  \times ( \sqrt{3}  -  \sqrt{6}) }{3 - 6}

Simplifying 2nd part

 \frac{4 \sqrt{3} }{ \sqrt{6}  +  \sqrt{2} }  \times  \frac{ \sqrt{6}  -  \sqrt{2} }{ \sqrt{6} -  \sqrt{2}  }

 \frac{4 \sqrt{3}  \times ( \sqrt{6}  -  \sqrt{2} )}{ {( \sqrt{6}) }^{2} -  {( \sqrt{2} }^{2} ) }  =  \frac{4 \sqrt{3} \times ( \sqrt{6}   -  \sqrt{2} )}{6 - 2}

Simplifying 3rd part

 \frac{ \sqrt{6} }{ \sqrt{2}  +  \sqrt{3} }  \times  \frac{ \sqrt{2}  -  \sqrt{3} }{ \sqrt{2} -  \sqrt{3}  }

 \frac{ \sqrt{6} \times ( \sqrt{2}  -  \sqrt{3} ) }{ {( \sqrt{2} }^{2}) -  {( \sqrt{3)} }^{2}  }  =  \frac{( \sqrt{12} -  \sqrt{18}  )}{2 - 3}

Putting all values we get;

(-√6 + √12) – (√18 - √6) + (-√12 + √18)

-√6 + √12 – √18 + √6 – √12 + √18

= 0

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