Math, asked by Terahero987, 1 year ago

I mark u in brilient list
Plz give me a answer of Question number 2

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Answers

Answered by Pranjal7905
1

Please check the attached

Attachments:
Answered by assthha161
0
Here is ur answer

x3+y3+z3−3xyz=

x3+y3+3x2y+3xy2+z3−3xyz−3x2y−3xy2

=(x+y)3+z3−3xy(x+y+z)

=(x+y+z)((x+y)2+
z2−(x+y)z)−3xy(x+y+z)

=(x+y+z)(x2+2xy+y2+z2−xy−3

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