I mirror of length 20 cm and width 15 cm is to
be framed with a 2 cm wide frame. Find the area
of the frame required. Also, find the cost of
framing at the rate of 15 per cm?
Answers
⛦ Given :
- Length of mirror = 20cm
- Breadth of mirror = 15cm
- Width of the frame = 2cm
⛦ To find :
- The area of the frame.
- The cost of framing at the rate of 15cm.
⛦ Solution :
First finding the Area of the mirror.
★Area of mirror = length × breadth
Area (mirror) = 20 × 15
Area (mirror) = 300 cm²
___________
Now, Area of mirror including the frame.
So,
- Length of mirror including the frame : 20 + 4 = 24 cm.
- Breadth of mirror including the frame : 15 + 4 = 19 cm.
Area of mirror including the frame
= 24 × 19
= 456 cm²
Now,
•Area of frame=Area of mirror including the frame -Area of mirror
Area of frame = 456 - 300
Area of frame = 156 cm²
So,
Cost of framing at ₹15 per cm.
Cost of framing 156 cm² :
⟼ ₹(156 × 15)
⟼ ₹2340
Therefore,
- Area of Frame required is 156 cm²
- Cost of framing is ₹2340
Answer:
Area of the required frame= 66cm².
Cost of Framing= Rs990.
Step-by-step explanation:
Given,
Dimensions of mirror= 20cm and 15cm
So, area= (20×15)cm²= 300cm²
New Dimensions= [(20-2)cm and (15-2)cm]
Therefore, New area= (18×13)cm²= 234cm²
Now, Area of Frame=Area of full mirror-Area of new mirror formed
Area of Frame= (300-234)cm²= 66cm².
Therefore, Cost of framing= Rate of framing×Area
Cost= Rs15×66cm²= Rs990
So, the area of Frame is 234cm² and the cost of framing it is Rs990.
Hope you get this!!