Question

I mole of FSU,
I mole of Cach = llig - 6.022 * 10 formula units
I mole of OH = 17 g = 6.022 * 10+ ions
tionships
The relationships between amounts of substances in term of their masses and
her of particles present in them are
Mass of the element
Number of atoms of an element
X Na
Atomic mass
Mass of compound
Number of molecules of a compound =
XNA
Molecular mass
Mass of the ion
Number of ions of ionic specie
X NA
Ionic mass
Q. Which of the following
contains the largest
number of atoms?
(a) Bg of methane
(b) +58 of hydrogen fluoride
(c) 15.66 af henzene
(d) 21.8g of bromoethane
Na dlound
ARD'S heels
The largest number of molecules are present in
(Lhr, Mtn 15, D.G Khan 09, Fsd 10)
(a) 3.6 g of H2O
(b) 4.8 g of C H OH
(c) 2.8 g of CO
(d) 5.4 g of N2Os
The mass of one mole of electrons is
(Mtn, Swl, Grw 15, Lhr 12, Fsd 07, Rwp 07)
(a) 1.0088
(b) 0.55 mg
(c) 0.184 mg
(d) 1,673 mg
In combustion analysis water vapours are absorbed in
(Fsd 08, Lhr 07)
(a) 50% KOH
(b) Mg(C1O4)2
(c) NaOH
(d) MgCl2
The number of molecules in one gram molecule of Co, is
(Grw 10)
(a) 6.02 x 10
(b) 6.02 x 10-2
(c) 6.27 x 1027
(d) 6.02 x 10
The mass of CO, containing 8 grams of oxygen (O2) in gram is
(Lhr 15 G-II, Grw 15 G-I, Bwp 15 G I)
(a) 32
(b) 22
(d) 11
Formula mass of CaCO, is
(Lhr (9)
(b) 90
(c) 120
(d) 106
Mass of electron is
(Lhr 11, Grw 14, 15)
(a) 9.1095x10-" kg (b) 9.1095 x 10 kg (c) 9.1095 x 10-7 kg (d) 9.1095 x10 g
(c) 16
(a) 100​

Answer 1

Answer:

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Explanation:

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