Question

I n compound was found to have 78.2% baron
and 21.8%
hydrogen (H). If molecular
mass determine to be 27.6u and what is the
molecular and empirical formula of
compound boron=11u and H=1u​

Answer 1

Answer:

Element

Mass (g)

78.2 21.8

Moles

78.2/10.8 21.8/1

(moles = mass/molar mass of atoms of the

element)

Ratio 7.24

Divide by 7.24/7.24 21.8/7.24

(this makes the number of atoms of the

smallest one = 1)

Approx

Approx 3

Empirical (simplest) formula = BH3

smallest 3.01

This has a formula mass of 10.8 + 1 x 3 = 13.8

So the molecular formula is 27.6/13.8 = 2.0

times bigger than the empirical formula

So molecular formula is B2H6

Hope you understand

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