Question

I need 4) question answer ​

Answer 1

HEY MATE HERE IS YOUR ANSWER:-

By the pythagoras theorem,

OM² = MA²+OA²

OM²-OA² = MA²

10²-6² = MA²

8 = MA

The length of chord is 8cm

HOPE THIS HELPS YOU MATE AND PLEASE MARK ME AS BRAINLY

Answer 2

Given:-

Given that, radius of a circle is 10cm and distance of a chord from the centre is 6cm.

To find:-

We have to find the length of the chord (AB).

Solution:-

Let :

• X be the centre of the circle.
• AB be the chord.
• XA be the radius = 10cm
• XC be the distance between the chord and the centre = 6cm

Here, XC is perpendicular to AB. In a right angled ∆XAC, by pythagoras theorem :

• AC² + XC² = XA²
• AC² + (6cm)² = (10cm)²
• AC² = 100cm² - 36cm²
• AC² = 64cm²
• AC = √64cm²
• AC = 8cm

We know that, the perpendicular drawn from the centre of a circle to a chord, bisects the chord.

So,

• AB = 2(AC)
• AB = 2(8cm)
• AB = 16cm