Question

I need 7 answer.......

Answer 1

angle A = 180°-(45°+55°)=180°-100°=80°
angle A is bisected by AD
thus angle BAD and angle DAC are equal=40° each
angle BDA=180°-(45°+40°)=180°-85°=95°
angle sum property of a triangle
angle ADC=180°-95°=85°
linear pair

Answer 2

In ∆ABC,
angle B = 45° and angle C = 55°.
Let angle A be x.
Then x + 45 + 55 = 180°
= x + 100 = 180°
= x = 180 - 100
= x = 80°
Then, angle ABD = angle DAC = 40° (because AD bisects angle A)
Then, angle ADB will be
45 + 40 + ADB = 180°
ADB + 85° = 180°
ADB = 95°
Also, angle ADC will be
40 + 55 + ADC = 180°
ADC = 180° - 95°
ADC = 85°.
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