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Two cars are moving towards each other on a straight road with velocity 10m/sec and 12m/sec respectively. When they are 160 metre apart, then each car decelerates at 2m/sec^2 until they stop in order to avoid collision. Calculate the distance between them when they come to rest.
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Two cars are moving towards each other on a straight road with velocity 10m/sec and 12m/sec respectively. When they are 160 metre apart, then each car decelerates at 2m/sec^2 until they stop in order to avoid collision. Calculate the distance between them when they come to rest.
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Can you tell me what is degradation of energy
loss of energy
Definition of degradation of energy. physics. : the process by which energy becomes less available for doing work — compare conservation of energy, dissipation of energy.
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Two cars are moving towards each other on a straight road with velocity 10m/sec and 12m/sec respectively. When they are 160 metre apart, then each car decelerates at 2m/sec^2 until they stop in order to avoid collision. Calculate the distance between them when they come to rest.
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t^o2 -20to+10= 0…………….(2)
Then, to=[20 +_sqrt(400–40)]/2 or
to=10 -9.49=0.51s or19.49s
During time 0.51s ,car 2 travels the road distance ,
d=20(0.51)=10.2m
Now, look at time t=19.49s
At this time car 1 moves with velocity v1=38.98 m/s . The distance it covers is d1=(1/2)(2)(19.49)^2=379.9m.
In this time car 2 moves through distance, d2=(19.49)(20)=389.8m.
So ,at this time car 2 again over takes the car 1.
Then, to=[20 +_sqrt(400–40)]/2 or
to=10 -9.49=0.51s or19.49s
During time 0.51s ,car 2 travels the road distance ,
d=20(0.51)=10.2m
Now, look at time t=19.49s
At this time car 1 moves with velocity v1=38.98 m/s . The distance it covers is d1=(1/2)(2)(19.49)^2=379.9m.
In this time car 2 moves through distance, d2=(19.49)(20)=389.8m.
So ,at this time car 2 again over takes the car 1.
Do it in this method
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