Math, asked by singhparvinder21946, 5 hours ago

i need a help
please tell me ​

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Answers

Answered by yashikaagrawalixe
0

Answer:

Using a³+b³+c³-3abc=(a+b+c)(a²+b²+c²-ab-bc-ca)

(a+b+b+c+c+a){(a+b)²+(b+c)²+(c+a)²-(a+b)(b+c)-(b+c)(c+a)-(c+a)(a+b)

(2a+2b+2c)(a²+b²+2ab+b²+c²+2bc+c²+a²+2ca-ab-ac-b²-bc-bc-ab-c²-ac-ac-bc-a²-ab)

(2a+2b+2c)(a²+b²+c²+2ab-3ab+2bc-3bc+2ca-3ac)

(2a+2b+2c)(a²+b²+c²-ab-bc-ac)

Hope it helps you!

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