i need a short method to prove √2 as irrational.
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let √2 be a rational number.
√2 = p/q
squaring on both sides,
2 = p²/q²
2q² = p²
2 divides p² then 2 also divides p,
so, p = 2a (a is any positive integer)
2q² = p²
2q² = (2a)²
2q² = 4a²
q² = 2a²
2 divides q² then 2 also divides q.
both p and q have 2 as common factor.
but this contradicts the fact that p and q are co-primes.
so,our supposition is false,
therefore, √2 is irrational number.
√2 = p/q
squaring on both sides,
2 = p²/q²
2q² = p²
2 divides p² then 2 also divides p,
so, p = 2a (a is any positive integer)
2q² = p²
2q² = (2a)²
2q² = 4a²
q² = 2a²
2 divides q² then 2 also divides q.
both p and q have 2 as common factor.
but this contradicts the fact that p and q are co-primes.
so,our supposition is false,
therefore, √2 is irrational number.
sandhya1511:
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