Question

i need all answers ​

Answer 1

25.) - (C) 0

let actual mean = x

and assumed mean = x

by both the methods mean = x

thus by assumed mean method

$a \: + \frac{Σfidi}{Σfi}$

To get the same answer Σfidi needs to be 0 thus;

• a + 0/Σfi
• a = x (actual mean)

26.) - (A)2/3

$\frac{de}{bc} = \frac{2}{5} \\ thus \: by \: similar \: triangles \: using \: aa \: similarity \: \\ \frac{ae}{ac} = \frac{2}{5} \\ \\ \frac{ac}{ae} = \frac{5}{2} \\ \\ \frac{ac}{ae} - 1 = \frac{5}{2} - 1 \\ \\ \frac{ec}{ae} = \frac{3}{2} \\ \\ \frac{ae}{ac} = \frac{2}{3}$

27.) - (C) (ax+by)/(x+y)

$mean = \frac{Σfixi}{Σfi} \\ = \frac{f1x1 + ....fnxn}{f1 + .......fn} \\ = \frac{ax + by}{x + y}$

(as a & b are xi or observation) &

(as x & y are fi or frequencies)

#answerwithquality

#BAL