i need ans for this plzz
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For the equation to have equal roots, the discriminant should be zero.
Here, it is
4(k+1)² = 4(3k+1)(k)
k²+2k+1 = 3k²+k
2k²-k-1 = 0 ⇒ 2k² - 2k+k - 1 = 0 ⇒ (2k+1)(k-1) = 0
So, k = -1/2 or k = 1
Here, it is
4(k+1)² = 4(3k+1)(k)
k²+2k+1 = 3k²+k
2k²-k-1 = 0 ⇒ 2k² - 2k+k - 1 = 0 ⇒ (2k+1)(k-1) = 0
So, k = -1/2 or k = 1
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