Question

I need ans of question 4th pls ans to be brainlist.

Answer 1

hello friend!!!
here you go
first lets find the coefficients a=4:b=5√2:c=-3 
lets factorise 
4x²+5√2x-3
lets split the middle term
4x²+6√2x-√2x-3
now take the common factors out
2√2x(√2x+3)-1(√2x+3)
=(√2x+3)(2√2x-1)
now equate each with 0
√2x+3=0
x=-3/√2
2√2x-1=0
x=1/2√2
therefore zeroes are -3/√2 and 1/2√2
verification
the first relation is that the sum of the zeroes = -b/a( we found the coefficients first)
therefore
-3/√2 + 1/2√2=-5/4
-5/4=-5/4
next relation is that the product of the zeroes = c/a
-3/√2 ×1/2√2=-3/4
-3/4=-3/4
hence verified
if any doubt, be free to ask in the comments session
plz mark as brainliest