Question

i need answer...........

Answer 1

Let,

One's digit number be $<b>y</b>$

and, Tens digit number be $<b>x</b>$

Number formed = 10x + y

After $<u>reversing</u>$ the digits,

New number = 10y + x

Also, x > y [ Assumed ]

A.T.Q.

10x + y + 10y + x = 66

11x + 11y = 66

11 ( x + y ) = 66

$<i>x + y = 6</i>$ _______( 1 )

Also,

$<i>x - y = 2</i>$ _____( 2 )

Add ( 1 ) & ( 2 )

2x = 8

$<u>x = 4</u>$

Put this in ( 1 )

4 + y = 6

y = 6 - 4

$<u>y = 2</u>$

$<u><i><b>Number formed –</u></b></i>$

= 10 ( 4 ) + 2

= 40 + 2

= $<u><b><i>42</b></u></i>$

Answer 2

let the two digit no be in form 10x+y
also x>y
so x-y=2
also 10x+y+10y+x=66
11x+11y=66
11(x+y)=66
x+y=66/11
x+y=6
or,x=6-y
now substitute value of x in x-y=2 we get
6-y-y=2
6-2y=2
6-2=2y
4=2y
4/2=y
2=y
also x =6-y
x=6-2
x=4
Now the two digit no is 42 and it's reverse is 24


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