Question

I need answer fast ...plz help me
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Answer 1

Explanation:

Lambda (m) = K×1000/M

=(1.06×10^-2×1000)/0.1

= 106cm^2/mol ohm

Molar conductivity at infinite dilution

= lambda(m°) = (50.1+76.15) = 126.25cm^2/ohm mol

Degree of dissociation= alpha

=Lambda(m°)/lambda(m)

= 106/126.25 = 0.835

Dissociation constant (alpha)

=

c ×(alpha)^2/(1-alpha)

=0.1×(0.835)^2/1-(0.835)

=0.422