Question

I need answer for all these ,pl help me

Answer 1

1)- Zeroes of polynomial 2x²-3x+4 is the highest degree of the polynomial i.e. 2

2)- The value of p(x) at x=2 is
x²-3x-4=4-6-4 =-6

3)- Zero of 2x+3 is
2x+3=0
x=-3/2

4)- According to the question
the equation will be 5x-3
the zero of 5x-3is
5x-3=0
x=3/5

6)- If -4 is the zero of polynomial then
x²-x-(2k+2)=0
put x=-4
16+4-2k-2=0
18-2k=0
2k=18
k=9

7)- A). by using factorisation method (splitting the middle term)

10)- zeroes of 2-x²is
2-x²=0
x=+- √2

11)- by using product of zeroes= -coefficient of x/ coefficient of x³

product nd sm of zeroes=coefficient of x²/coefficient of x³

product of zeroes=-constant term/coefficient of x³

12)- p(x) = 4x⁴-20x³+23x²+5x-6
if zeroes are 2 nd 3then
g(x) =(x-2)(x-3)
=x²-5x+6
now dividing g(x) and p(x) we will get some quotient q(x) and remainder r(x) =0
using
p(x)=g(x).q(x)+r(x)
factorising q(x)
u will get the other two zeroes.