Question

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Answer 1

Question :

In a reaction, 5.3 g of sodium carbonate reacted with 6 g of ethanoic acid. The products were 2.2 g of CO₂, 0.9 g of water and 8.2 g of sodium ethanoate. Show that these observation are in agreement with the law of conservation of mass.

Sodium carbonate + Ethanoic acid $\longrightarrow$ Sodium ethaonoate + Carbon dioxide + Water

Explanation:

Here, we have to show that the given observations in the question are in agreement with the law of conservation of mass. Let's firstly understand the 'Law of conservation of mass'.

• Law of conservation of mass was given by Antoine Lavoisier.
• According to this law, Mass can neither be created nor be destroyed in a chemical reaction.

Or simply, we can say that :

$\boxed{\sf{Total \; mass \; of \; reactants = Total \; mass\; of \; products}}$

Here, mass of of reactants :

• Mass of Sodium carbonate = 5.3g
• Mass of Ethanoic acid = 6g

So,

→ Total mass of reactants = Mass of sodium carbonate + Mass of ethanoic acid

→ Total mass of reactants = 5.3g +6g

→ Total mass of reactants = 11.3 g … ( 1 )

And, the mass of products :

• Mass of sodium ethanoate = 8.2g
• Mass of carbon dioxide = 2.2g
• Mass of water = 0.9 g

→ Total mass of products = Mass of sodium ethanoate + Mass of carbon dioxide + Mass of water

→ Total mass of products = 8.2g + 2.2g + 0.9g

→ Total mass of products = 11.3g … ( 2 )

On observing ( 1 ) and ( 2 ), we get that :

Mass of reactants = Mass of products, here.

Hence, these observations are in agreement with the law of conservation of mass.

$\rule{200}2$

Answer 2

Refer the given attachment