Math, asked by shahid292005, 1 year ago

i need answer for this questionplease answer this question guys I don't know how to do this guys I'm giving 50 points for this question

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Answered by Harshscigen

since the sum of opposite angles of a cyclic quadrilateral is 180 deg.
therefore
x + 41 = 180
x = 180 - 41
x = 139
sum of the angles made on the one side of straight line is 180 deg
therefore
x + y =180
139 + y =180
y = 180-139
y = 41
now in the triangle CAE;
∠CEF is an external angletherefore∠CEF=∠ACE+∠CAE
external angle of a triangle is equal to the sum of two opposite angles
∠CEF=36+41=77and in triangle DEF;y+∠DEF+z=180 [sum of interior angles of a trianglez=180−(y+∠DEF)z=180−(41+∠CEF)z=180−(41+77)z=180−118=62

hope this helps you

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Answered by Anonymous

Answer:

since the sum of opposite angles of a cyclic quadrilateral is 180 deg.

therefore

x + 41 = 180

x = 180 - 41

x = 139

sum of the angles made on the one side of straight line is 180 deg

therefore

x + y =180

139 + y =180

y = 180-139

y = 41

now in the triangle CAE;

∠CEF is an external angletherefore∠CEF=∠ACE+∠CAE

external angle of a triangle is equal to the sum of two opposite angles

∠CEF=36+41=77and in triangle DEF;y+∠DEF+z=180 [sum of interior angles of a trianglez=180−(y+∠DEF)z=180−(41+∠CEF)z=180−(41+77)z=180−118=62

Read more on Brainly.in - https://brainly.in/question/8024744#readmore

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