i need answer for this simple question
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cos 37°×cosec 53°/sin 30°
= cos 37°/sin 30°× sin 53°
= cos 37°/sin30°× cos(90-53°)
= cos 37°/sin 30°× cos 37°
= 1/sin 30°
= cosec 30°
= 2
= cos 37°/sin 30°× sin 53°
= cos 37°/sin30°× cos(90-53°)
= cos 37°/sin 30°× cos 37°
= 1/sin 30°
= cosec 30°
= 2
ReetChauhan1112:
plz mrk as branliest
Answered by
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cos 37 * cosec53 / sin 30
=> cos37 / sin 30 * sin 53
=> cos 37 / sin 30* cos 37
=> 1/ sin 30
=> cosec 30
=> 2
hope it helps
Mark as brainliest plz if you like
=> cos37 / sin 30 * sin 53
=> cos 37 / sin 30* cos 37
=> 1/ sin 30
=> cosec 30
=> 2
hope it helps
Mark as brainliest plz if you like
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