i need answer of this too...
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using conservation of momentum
initial momentum=final momentum
about y axis
Mv0 *sin90°+0=(3M+M)v sina
or. v=v0/4coseca
about x axis
all parameters are zero
now using conservation of energy about y axia
½M(V0)²=½4M(V0/4)² cosec²a
or 4=cosec²a
or a=30°
and velocity of centre of mass is
V0/4 *cosec30°
=V0/2
Hope it is right
initial momentum=final momentum
about y axis
Mv0 *sin90°+0=(3M+M)v sina
or. v=v0/4coseca
about x axis
all parameters are zero
now using conservation of energy about y axia
½M(V0)²=½4M(V0/4)² cosec²a
or 4=cosec²a
or a=30°
and velocity of centre of mass is
V0/4 *cosec30°
=V0/2
Hope it is right
Tamash:
ok i 'll try........
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Actually i'm busy with marriage ceremony of my causign....
i 've read but couldn't able to reply due to shortage of time...
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