Question

I need answer quick​

Answer 1

Solution :-

Given that ,

= EF//GH

And , AC is line between them .

So ,

<EAC = <ACH (Alternate angles)

Now , <ACH = 120°

So ,

<EAC = 120°

<EAG +<BAC = 120°

70° +<BAC = 120°

<BAC = 50°

Now,

<ACH +<ACB = 180 ° (Linear pair )

120° + < ACB = 180°

<ACB = 60°

EAG + BAC +CAF = 180 (Linear pair )

70°+50°+CAF = 180°

CAF = 60°

Now ,

Sum of CAF and BAC ,

= 60° + 50°

= 110°

Hope it helps you :))