Question

I need answer quickly

Answer 1

Answer:

none of these

Step-by-step explanation:

function is y1+x+2

=none of tese

Answer 2

Answer:

Log can't take negative values

$1 - x > 0 = = x < 1$

Root can't take negative values

$x + 2 \geqslant 0 \: \: = = \: \: x \geqslant -2$

There can't be a zero in denominator

$log(1 - x) \neq0 \\ 1 - x \neq 1 \\ x \neq0$

Take intersection of all three , we get

$x \in \: [-2 , 1)-{0}$

Answer - 2